The graph of a function f is given belowThe xy-coordinate plane is given.The curve starts at the point (-3, 2), goes down and right, crosses the x-axis at approximately x =-2.5, passes through the approximate point-2,-1.1 changes direction at the point(-1,-2),goes up and right, passes through the point (0, -1), crosses the x-axis at approximately x = 0.3 passes through the point(1,2passes through the approximate point (2, 2.8), and ends at the point3,3(a)State the value of f(-1)f(-1)=(b) Estimat
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SOLVED:You are given a function and a specified point on its graph. (a) Graph the function, and (b) on the same axes, graph three secant lines through the given point using Δt=1,0.5,0.01. Then (c) based on those secant lines, approximate the slope of the tangent line to the graph of f at the given point. f(t)=e^-t ;(0,1)
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