Solution: det (A) = −5, and for n×n matrix adj (A) has determinant (det A)^ (n−1). Here n = 3, so det (B) = (−5)^ (2) = 25. For feedback or story ideas, reach us at timesnoweducation@timesgroup.com ...

We have looked at how to solve equations with one unknown value, but what happens when there are two unknown values? An equation with two unknown values will have infinitely many solutions. or \(x=100 ...