First, we need to find which number when substituted into the equation will give the answer zero. \(f(1) = {(1)^3} + 4{(1)^2} + (1) - 6 = 0\) Therefore \((x - 1)\)is a factor. Factorise the quadratic ...

A topological formula of the loop expansion of the colored Jones polynomials A topological formula of the loop expansion of the colored Jones polynomials 早稲田 ...